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**General Questions and Discussion / Re: Maximum number of particles for MCTDHB**

« **on:**September 03, 2020, 09:34:31 AM »

Hi Asaad Sakhel!

The accuracy of MCTDH-B is dependent on the physical situation that is considered.

The size of the configuration space is N+M-1 choose N ; so for N=2000 particles you can work at most with M=3 orbitals.

If these 2003001 configurations would be a sufficiently large configuration space for the system you have in mind, then yes.

For instance, I think you could get a very accurate representation for harmonically, double-well, and triple-well trapped particles.

There exist many examples where MCTDH-B has been applied for N>200, for instance:

https://www.pnas.org/content/109/34/13521

https://journals.aps.org/prl/pdf/10.1103/PhysRevLett.106.240401

https://journals.aps.org/prl/abstract/10.1103/PhysRevLett.100.130401

Best,

Axel

The accuracy of MCTDH-B is dependent on the physical situation that is considered.

The size of the configuration space is N+M-1 choose N ; so for N=2000 particles you can work at most with M=3 orbitals.

If these 2003001 configurations would be a sufficiently large configuration space for the system you have in mind, then yes.

For instance, I think you could get a very accurate representation for harmonically, double-well, and triple-well trapped particles.

There exist many examples where MCTDH-B has been applied for N>200, for instance:

https://www.pnas.org/content/109/34/13521

https://journals.aps.org/prl/pdf/10.1103/PhysRevLett.106.240401

https://journals.aps.org/prl/abstract/10.1103/PhysRevLett.100.130401

Best,

Axel